# Ejercicio Seccion Minima Infiltracion

• January 2021
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EJERCICIO 2 Determinar la geometría que se le debe dar a un canal de mínima infiltración que debe trasmitir un caudal de 8000 lt/seg. Con los siguientes datos: Talud: Z =2 Rugosidad: n = 0.010 Pendiente: S = 5x10-4

SOLUCION Para canales de mínima infiltración se tiene: 𝑚=

𝑏 𝜃 = 4 𝑡𝑎𝑛 = 4 (√1 + 𝑍 2 − 𝑍) 𝑦 2

𝑏 = 4 (√1 + 22 − 2) 𝑦 𝑏 = 0.944 𝑦 𝑏 = 0.944𝑦 Área de la sección transversal y perímetro mojado: 𝐴 = 𝑏𝑦 + 𝑍𝑦 2 𝐴 = 𝑏𝑦 + 2𝑦 2 𝐴 = (0.944𝑦)𝑦 + 2𝑦 2 𝐴 = 2.944𝑦 2

𝑃 = 𝑏 + 2 (√𝑍 2 + 1) 𝑦 𝑃 = 0.944𝑦 + 2 (√22 + 1) 𝑦 𝑃 = 5.416𝑦 Procedemos a calcular el Radio hidráulico: 𝑅=

𝐴 𝑃

2.944𝑦 2 𝑅= 5.416𝑦 𝑅 = 0.544𝑦 Aplicando la Ecuación de Manning: 2 1

𝐴𝑅3 𝑆 2 𝑄= 𝑛 2

1

(2.944𝑦2 )(0.544𝑦)3 (5 × 10−4 )2 8= 0.010

𝑦 = 1.253𝑚

𝑏 = 1.183𝑚

… Tirante

… Ancho de solera

Con lo cual nuestra sección transversal de canal queda de la siguiente forma:

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