Predimensionamiento De Columnas
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DiseΓ±ar una columna cuadrada sujeta a carga axial pura Pu
=
150
f'c fy
= =
210 4200
T Kg/cm2 Kg/cm2
Solucion: 1.- Dimensionamiento π¨π β₯
π·π π. ππ(πβ²π + π . ππ )
Ag
β₯
Ag
= 1133.79
150000 0.45 (210 + 0.02 x 4200)
Adoptamos S = T = Ag
=
35 35 1225
cm2
cm cm cm2
2.- Refuerzo Longitudinal π·π = π. ππ π. ππ β πβ²π π¨π β π¨π + ππ β π¨π
150000 = 0.8 [0.85 x 210 (1225 - As) + 4200 x As] ########## As
=
12.23
cm2
π¨π πππ = π. ππ π π¨π
Asmin = 0.01 x 1225 Asmin =
12.25
cm2
As
=
12.25
cm2
Usar :
4ΓΈ
As
=
13.00
NΒ° 5
+
4ΓΈ
NΒ° 4
cm2
NΒ° 5 NΒ° 4
0.35 m
0.35 m
DiseΓ±ar una columna cuadrada sujeta a carga axial pura Pu
=
150
f'c fy
= =
1000 4200
T Kg/cm2 2 Kg/cm
Solucion: 1.-
Dimensionamiento π¨π β₯
Ag Ag
β₯
150000 0.45 (1000 + 0.02 x 4200) cm2
=
307.50
Adoptamos S = T =
25 25
cm cm
625
cm2
Ag 2.-
π·π π. ππ(πβ²π + π . ππ )
=
Refuerzo Longitudinal π·π = π. ππ π. ππ β πβ²π π¨π β π¨π + ππ β π¨π
150000 = ########## As
=
0.8 [0.85 x 1000 (625 - As) + 4200 x As] -78.62
cm2
π¨π πππ = π. ππ π π¨π
Asmin =
0.01 x 625
Asmin =
6.25
cm
As
=
6.25
cm2
Usar :
2ΓΈ
As
=
6.50
2
NΒ° 3 cm
+
4ΓΈ
NΒ° 4
2
NΒ° 3 NΒ° 4
0.25 m
0.25 m
=
150
f'c fy
= =
210 4200
T Kg/cm2 Kg/cm2
Solucion: 1.- Dimensionamiento π¨π β₯
π·π π. ππ(πβ²π + π . ππ )
Ag
β₯
Ag
= 1133.79
150000 0.45 (210 + 0.02 x 4200)
Adoptamos S = T = Ag
=
35 35 1225
cm2
cm cm cm2
2.- Refuerzo Longitudinal π·π = π. ππ π. ππ β πβ²π π¨π β π¨π + ππ β π¨π
150000 = 0.8 [0.85 x 210 (1225 - As) + 4200 x As] ########## As
=
12.23
cm2
π¨π πππ = π. ππ π π¨π
Asmin = 0.01 x 1225 Asmin =
12.25
cm2
As
=
12.25
cm2
Usar :
4ΓΈ
As
=
13.00
NΒ° 5
+
4ΓΈ
NΒ° 4
cm2
NΒ° 5 NΒ° 4
0.35 m
0.35 m
DiseΓ±ar una columna cuadrada sujeta a carga axial pura Pu
=
150
f'c fy
= =
1000 4200
T Kg/cm2 2 Kg/cm
Solucion: 1.-
Dimensionamiento π¨π β₯
Ag Ag
β₯
150000 0.45 (1000 + 0.02 x 4200) cm2
=
307.50
Adoptamos S = T =
25 25
cm cm
625
cm2
Ag 2.-
π·π π. ππ(πβ²π + π . ππ )
=
Refuerzo Longitudinal π·π = π. ππ π. ππ β πβ²π π¨π β π¨π + ππ β π¨π
150000 = ########## As
=
0.8 [0.85 x 1000 (625 - As) + 4200 x As] -78.62
cm2
π¨π πππ = π. ππ π π¨π
Asmin =
0.01 x 625
Asmin =
6.25
cm
As
=
6.25
cm2
Usar :
2ΓΈ
As
=
6.50
2
NΒ° 3 cm
+
4ΓΈ
NΒ° 4
2
NΒ° 3 NΒ° 4
0.25 m
0.25 m
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