Makalah Seminar Penelitian Teknik Kimia, Fti, Upn “veteran” Yogyakarta

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Makalah Seminar Penelitian Teknik Kimia, FTI, UPN “Veteran” Yogyakarta

Maka :

Qgas hasil =

= 1,3109 kg/jam 

Menghitung NHVgas hasil : Qgas hasil = 1,3054 m3/jam Komposisi gas hasil : CO

= 0,262956

CH4

= 0,025061

H2

= 0,164820

NHV CO ( kkal/mol )

= 63,6361

NHV CH4 ( kkal/mol )

= 191,759

NHV H2 ( kkal/mol )

= 57,7979

Maka NHVgas hasil = Y CO . BM CO + Y H2 . BM H2 + Y CH4 . BM CH4 = (0,262956 x 63,6361) + (0,164820 x 57,7979) + (0,025061 x 191,759) kkal/mol = (16,7335 + 9,5262 + 4,8057) kkal/mol x 1000 mol/1 kmol = 31065,4 kkal/mol x 1 kmol/22,4 Nm3 = 1386,85 kkal/Nm3 NHVgas hasil

= 1386,85 kkal/Nm3

Kalor gas hasil per jam

Fitria Yusticia

= Qgas hasil x NHVgas hasil x

( 121 090 005 )

Tahan Franciskus Sianturi ( 121 090 007 )

Makalah Seminar Penelitian Teknik Kimia, FTI, UPN “Veteran” Yogyakarta

= 1,3054 m3/jam x 1386,85 kkal/Nm3 x `

= 1625,7814 kkal/jam

Kalor dari batubara / jam

= Laju umpan batubara hasil x nilai kalor batubara

Laju umpan batubara = 15 gram/menit x

x

= 0,9 kg/jam Kalor dari batubara / jam

= 0,9 kg/jam x 5312 kkal/kg = 4780 ,8 kkal/jam



Menghitung Effisiensi thermal Effisiensi thermal (η) =

=

η

= 37,25 %

Dengan cara perhitungan yang sama didapat NHVgas hasil dan effisiensi thermal sebagai berikut: Parameter NHV (Net Heating Value) , (kkal/Nm3) Effisiensi Thermal (η) (%)

Fitria Yusticia

Run 1

Run 2

Run 3

Run 4

Run 5

Run 6

218.8520 4.55

1290.0469 24.77

1413.9435 38.06

218.8520 1.3

1290.0469 18.36

1386.85 37.25

( 121 090 005 )

Tahan Franciskus Sianturi ( 121 090 007 )

Makalah Seminar Penelitian Teknik Kimia, FTI, UPN “Veteran” Yogyakarta

Fitria Yusticia

( 121 090 005 )

Tahan Franciskus Sianturi ( 121 090 007 )

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