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ALGEBRA CE Review May 2021 (EERC)
Page 1 of 6
ALGEBRA BINOMIAL/MULTINOMIAL EXPANSION 1.
In the expansion of (x + 4y)12, the numerical coefficient of the 5th term is:
2.
3.
4.
a.
253 440
c. 63 360
b.
126 720
d. 506 880
The term involving y4 in the expansion of (3x – y)11 is: a.
721 710 x7y4
c. – 721 710 x7y4
b.
727 110 x7y4
d. – 727 110 x7y4
The term involving x9 in (x2 +
2 12 ) x
is:
a.
32 168 x9
c. 6 987 x9
b.
25 344 x9
d. 512 x9
Find the term in (a + 2b – c)10 that involves a4c3 a.
33 600 a4b4c3
c. – 33 600 a4b4c3
b.
33 600 a4b3c3
d. – 33 600 a4b3c3
Solve for the value/s of x in the equation: 5x2 – 6x - 9 = 0
6.
a.
2.07, 0.87
c. 2.07, - 0.87
b.
– 2.07, 0.87
d. – 2.07, - 0.87
Solve for x in the equation: x=1+
1 1+
1
1 1+ 1+…
9.
a.
1.390
c. 1.521
b.
1.483
d. 1.618
What is the sum of the roots? a.
3
c. 6
b.
–3
d. – 6
a.
27
c. – 27/2
b.
– 27
d. 27/2
Find the quadratic equation if one of the roots is 8 – 3i. 2
x + 16x + 73 = 0
c.
x2 + 16x – 73 = 0
d.
x2 – 16x – 73 = 0
10. What is the value of k so that 4x + (4k – 3)x + 1 = 0 has two equal roots? a.
3/4
c. – 3/4
b.
– 1/4
d. 1/4
11. In a quadratic equation problem, one student made a mistake in copying the coefficient of x and got the roots 5 and – 3/2. Another student also made a mistake in copying the constant term and got the roots 2/3 and 1/4. Find the correct quadratic equation. a.
SITUATION 2: For log 1 456 12. Determine its characteristic. a.
2
c. 4
b.
3
d. 5
13. Determine its mantissa. a.
0.1632
c. 0.8368
b.
– 0.1632 d. – 0.8368
SITUATION 3: For log 0.0000564302 14. Determine its characteristic. a.
–2
c. - 4
b.
–3
d. – 5
a.
0.2485
c. 0.7515
b.
– 0.2485
d. – 0.7515
16. Solve for x if logx 36 = 2. a.
2
c. 6
b.
4
d. 8
a.
2
c. 6
b.
4
d. 8
a.
2
b.
4
c. 6
ex ) ex-2
d. 5 x
2x + 1
19. Solve the equation (3 )(5
) = 63x – 2
a.
4.9902
c. 4.9920
b.
4.9092
d. 4.2099
20. The polynomial x3 + 4x2 – 3x + 8 is divided by x – 5, then the remainder is: a.
175
c. 218
b.
140
d. 200
21. Find the remainder if we divide 4y3 + 16y2 + 8y – 4 by a.
10
c. 15
b.
11
d. 13
22. Given f(x) = (x + 3)(x – 4) + 4. When f(x) is divided 2
2
LOGARITHMS
(2y + 3)
x2 – 16x + 73 = 0
b.
d. 12x2 – 11x – 90 = 0
REMAINDER AND FACTOR THEOREM
What is the product of the roots?
a.
12x2 + 11x – 90 = 0
18. Find the value of y in the equation y = ln(
x2 + 6x – 27 = 0
8.
c.
17. Find a if log2(a + 2) + log2(a – 2) = 5.
SITUATION 1: Given the quadratic equation: 7.
12x2 – 11x + 90 = 0
15. Determine its mantissa
QUADRATIC EQUATIONS 5.
b.
12x + 11x + 90 = 0.
by (x – k), the remainder is k. What is the remainder? a.
2
c. 6
b.
4
d. 8
NUMBER/DIGIT PROBLEMS 23. The sum of five consecutive even integers is 1280. Find the product of the lowest and highest integer. a.
64 512
c. 65 532
b.
65 024
d. 65 520
JOHN REY M. PACTURANAN, CE, MP
ALGEBRA CE Review May 2021 (EERC)
Page 2 of 6
24. The sum of the digits of a two – digit number is 10.
a.
26 y.o.
c. 42 y.o.
If the number is divided by the units’ digit, the
b.
30 y.o.
d. 36 y.o.
quotient is 3 and the remainder is 4. Find the
32. The sum of the parents’ ages is twice the sum of the children’s ages. Four years ago, the sum of the
number. a.
37
c. 46
parents’ ages was thrice the sum of the children’s
b.
28
d. 19
ages. In 16 years, the sum of the ages of the
25. The sum of the digits of a three – digit number is 17.
parents and children will be equal. How many children
If the digits are reversed and the resulting number
are there?
is added to the original number, the result is 1 474.
a.
4
c. 5
b.
7
d. 6
If the resulting number is subtracted from the original number, the result is 396. Find the original
33. When John was as old as Paul is now, the sum of their ages was 51. When Paul will be as old as John is
number. a.
935
c. 854
now, the sum of their ages will be 103. John is older
b.
845
d. 953
than Paul by how many years?
PROPORTION/VARIATION PROBLEMS 26. z varies directly as x and inversely as the square
a.
25 years
c. 13 years
b.
19 years
d. 32 years
CLOCK PROBLEM
root of y. It is equal to 3 when x is 13 and y is 16. Find the value of z when x is 52 and y is 9.
34. At what time between 4:00 PM and 5:00 PM will the hands be coincident?
a.
24
c. 25
b.
20
d. 16
27. At constant temperature, the resistance of a wire
a.
4:21.82
c. 4:23.64
b.
4:22.27
d. 4:21.64
varies directly as its length and inversely as the
35. In how many minutes after 2 o’clock will the hands
square of its diameter. If a piece of wire 0.10 in in
of the clock extend in opposite directions for the
diameter and 50 ft long has a resistance of 0.10
first time?
ohm, what is the resistance of another piece of wire
a.
40.64 min
c. 42.64 min
b.
41.64 min
d. 43.64 min
of the same material, 2 000 ft long, 0.20 in in
36. Find the angle between the hands of the clock at
diameter? a.
0.50 ohm
c. 1 ohm
b.
4 ohms
d. 2 ohms
28. If three cats can kill three mice in three minutes, in how many minutes can twelve cats kill twelve mice?
3:43 PM. a.
148.500
b.
0
147.50
c. 145.500 d. 146.500
37. A man left his home at past 3:00 PM as indicated in
a.
12 min
c. 4 min
his wall clock. Between two or three hours after, he
b.
6 min
d. 3 min
returned home and noticed that the hands of the
29. Ten students from Pampanga decided to stay in
clock interchanged. At what time did he leave his
Manila for a regular review in preparation for the CE
home?
Board Exam. To minimize their expense, they agreed
a.
3:33.47
c. 3:32.47
to bring 18 sacks of rice that will last for 4 months.
b.
3:31.47
d. 3:34.47
After their regular review, 4 students went back to Pampanga. Only the remaining students enrolled in
MIXTURE PROBLEMS
the refresher for 1 month. How much more rice will the remaining students need for their extended stay in Manila? (1 sack = 50 kg)
38. A 50 mL 40% acid solution is added to 150 mL 30% acid solution. What will be the concentration of the
a.
120 kg
c. 150 kg
b.
135 kg
d. 175 kg
AGE PROBLEMS
resulting mixture? a.
25 %
c. 30 %
b.
27.5 %
d. 32.5 %
39. How much of a 90 % solution of insect spray must a farmer add to 200 cc of 40% insect spray to make a
30. Elmer is 36 years old and his daughter is 8 years old.
50% solution of insect spray?
In how many years will Elmer’s age be twice his
a.
30 cc
c. 50 cc
daughter’s age?
b.
40 cc
d. 60 cc
a.
20 years
c. 18 years
40. A container is filled with 70 L which is 40 % alcohol
b.
24 years
d. 22 years
by volume. How much of a mixture must be taken and
31. Two years ago, a father was four times as old as his son. In 3 years, the father will only be three times
then replaced with equal amount of water so that the resulting solution is 30 % alcohol by volume?
as old as his son. How old was the father when his
a.
17.50 L
c. 20 L
son was born?
b.
15 L
d. 22.50 L
JOHN REY M. PACTURANAN, CE, MP
ALGEBRA CE Review May 2021 (EERC)
Page 3 of 6
41. A vat contains a mixture of acid and water. If 25
49. Twenty – eight men can finish the job in 60 days. At
gallons of acid are added, the mixture will be 80 %
the start of the 16th day, 5 men were laid off and
acid. If 25 gallons of water are added, the mixture
after the 45th day, 10 more men were hired. How
will be 60 % acid. Find the percentage of acid in the
many days were they delayed in finishing the job?
mixture. a.
65 %
c. 75 %
b.
70 %
d. 72 %
a.
2.27 days
c. 2.97 days
b.
2.45 days
d. 3.67 days
VENN DIAGRAM MOTION PROBLEM 42. Two airplanes left airports which are 960 km apart
50. In a certain group of consumers, each one may drink
and flew toward each other. One plane flew 32 kph
beer, and/or brandy, and/or whisky, or all. Also, 155
faster than the other. If they passed each other at
drink brandy, 173 drink beer, 153 drink whisky, 53
the end of an hour and 12 minutes, what was the
drink beer and brandy, 79 drink beer and whisky, 66
rate of faster plane?
drink brandy and whisky, 21 of them drink beer,
a.
352 kph
c. 416 kph
brandy and whisky. How many are there in the
b.
384 kph
d. 448 kph
group?
43. The boat travels downstream in two – thirds the time as it does upstream. If the speed of the river current is 8 kph, determine the velocity of the boat in still water.
a.
302
c. 304
b.
303
d. 305
51. The probability of the students passing Chemistry and Physics are 40 % and 55 %, respectively. If
a.
30 kph
c. 50 kph
there are 260 students who took the exam and 37
b.
40 kph
d. 60 kph
of them failed in both subjects, how many students
44. A man walks from his house to the office. If he
passed both subjects?
leaves at 8:00 AM and walks at the rate of 2 kph, he will have arrived 3 minutes earlier, but if he leaves
a.
20
c. 27
b.
28
d. 24
at 8:30 AM and walks at 3 kph, he will have arrived 6
52. CSPC CE 5 students took an examination on
minutes late. What time should he arrive at the
Geometry, Calculus, Probability and Engineering
office?
Economy. The results are as follows:
a.
9:06 AM
c. 8:54 AM
b.
9:12 AM
d. 8:43 AM
45. A man started on his mountain bike for Manila, a
178 Passed Engineering Economy 172 Passed Probability
distance of 30 km, intending to arrive at a certain
177 Passed Calculus
time. After biking for 10 km, he was detained due to
161 Passed Geometry
the bad weather for half an hour. As a result, he had
65 Passed Probability and Engineering Economy
to speed up 2 km faster. What was his original
63 Passed Calculus and Engineering Economy
speed?
56 Passed Calculus and Probability
a.
8.50 kph
c. 7.50 kph
49 Passed Geometry and Engineering Economy
b.
8 kph
d. 9 kph
60 Passed Geometry and Probability 51 Passed Geometry and Calculus
WORK PROBLEMS
19 Passed Calculus, Probability and Engineering Economy
46. A can do a piece of work alone in 30 days, B in 20
20 Passed Geometry, Probability, and Engineering
days, and C in 60 days. If they work together, how many days would it take them to finish the work? a.
15 days
c. 10 days
b.
8 days
d. 12 days
47. A and B working together can finish the job in 10
Economy 15 Passed Geometry, Calculus, and Engineering Economy 16 Passed Geometry, Calculus and Probability 6 Passed all subjects
days. If A works 4 days and B works 3 days, onethird of the job shall be finished. How many days will
If there were 93 students who did not pass in any
it take A to finish the job alone?
subject, how many students took the examination?
a.
30 days
c. 20 days
a.
498
c. 500
b.
15 days
d. 45 days
b.
499
d. 501
48. Eight men can excavate 50 m of canal in 7 hours. Three men can backfill 30 m of the excavated canal
ARITHMETIC SEQUENCE AND SERIES
in 4 hours. How long would it take 10 men to dig and backfill 100 m of canal?
SITUATION 4: Given the sequence 15, 18, 21, …
a.
12.50 hrs
c. 21.50 hrs
b.
15.20 hrs
d. 25.10 hrs
53. Determine the 30th term. a.
153
JOHN REY M. PACTURANAN, CE, MP
c. 120
ALGEBRA CE Review May 2021 (EERC) b.
Page 4 of 6
102
d. 135
54. What is the order of “93” in the sequence?
66. Find the sum of the geometric progression 2x, 4x + 14, 20x – 14, … up to the 10th term.
a.
27
c. 29
a.
566 579
c. 617 774
b.
28
d. 30
b.
312 228
d. 413 336
55. Determine the sum of first 20 terms. a.
840
c. 870
b.
900
d. 930
56. How many terms of the sequence are needed in order to obtain a sum of 1188?
67. Find the geometric mean of 2.138, 6.414, 19.242, and 57.726. a.
10.367
c. 11.109
b.
10.995
d. 12.607
68. A container is filled with 20 gallons of pure water.
a.
21
c. 23
Five gallons of water is taken from the container and
b.
22
d. 24
is replaced by 5 gallons of pure acid and then thoroughly mixed. Another 5 gallons is taken from
57. Find the sum of all odd numbers between 100 and 1000.
the mixture and is replaced again by 5 gallons of pure acid. If this process is done repeatedly, find
a.
472 500
c. 247 500
the amount of water in the container after doing the
b.
427 500
d. 274 500
process 15 times.
2
2
58. If the term 3(x -1), x – 4x + 5, 11 – 9x form an arithmetic progression, find the sum of the first 8
a.
0.672 gal
c. 0.276 gal
b.
0.267 gal
d. 0.627 gal
69. A ball is dropped from a height of 48 ft and
terms. a.
– 144
c. - 160
rebounds two-thirds of the distance it falls. If it
b.
– 168
d. – 152
continues to fall and rebound in this way, how far will
59. A particle moves along a straight path. For the first
it travel before coming to rest?
second, it travels 16 m. In every second after the
a.
120 ft.
c. 240 ft.
first, it travels 2 m farther than it did in the
b.
192 ft.
d. 200 ft.
preceding second. How far will it travel after 10 HARMONIC SEQUENCE AND SERIES
seconds? a.
250 m
c. 180 m
b.
34 m
d. 92 m
60. In the recent “Gulf War” in the Middle East, the Allied Forces captured 6 390 of the Saddam’s soldier with provisions on hand that will last for 216 meals taking 3 meals a day. The provisions lasted 9 more days because of daily deaths. At an average, how many captured soldiers died per day? a.
15
c. 17
b.
16
d. 18
70. Find the 20th term of the harmonic progression 1/2, 1/5, 1/8, … a.
1/50
c. 1/56
b.
1/53
d. 1/59
71. The 3rd term of a harmonic progression is 15 and the 9th term is 6. Find the 11th term. a.
4
c. 6
b.
5
d. 7
72. The geometric mean and the arithmetic mean of two numbers are 8 and 17, respectively. Find the
GEOMETRIC SEQUENCE AND SERIES SITUATION 5: Given the sequence 2, 6, 18, … 61. What is the 15
th
harmonic mean. a.
3.45
c. 3.54
b.
3.76
d. 3.67
73. A race is scheduled for four laps. The velocities of a
term?
a.
9 565 938
c. 9 656 938
car for these laps are 60 kph, 56 kph, 52 kph, and
b.
9 556 938
d. 9 665 938
63 kph, consecutively. Find its average velocity for
62. In what order of the sequence is 354 294?
the whole race.
a.
11
c. 13
a.
57.30 kph
c. 57.60 kph
b.
12
d. 14
b.
57.45 kph
d. 57.75 kph
63. What is the sum of the first 10 terms? a.
59 408
c. 59 048
b.
59 480
d. 59 084
64. How many terms of the sequence are needed in
SUMMATION 74. Evaluate: 10
order to obtain a sum of 6560? a.
7
c. 9
b.
8
d. 10
65. Find the sum of the infinite geometric progression 36. 24, 16, … a.
108
c. 160
b.
180
d. 116
a.
1.08
b.
1.18
� 1
75. Determine the value of:
JOHN REY M. PACTURANAN, CE, MP
1 2x+1 c. 1.28 d. 1.38
ALGEBRA CE Review May 2021 (EERC)
Page 5 of 6
15
a.
-0.934
b.
-0.439
88. What is the cofactor of A23?
2x � 6-3x2 8
c. -0.943
d. -0.493
MATRICES AND DETERMINANTS
a.
31
c. 13
b.
– 31
d. – 13
89. What is the cofactor of A31? a.
36
c. 63
b.
– 36
d. – 63
-1
SITUATION 6: Given the following matrices: 3 7 0 9 -2 5 A = -2 6 -9 B = 2 -3 7 1 -8 -3 -4 0 1 76. Find A + B 12 5 5 A + B = 0 3 -2 -3 -8 -2 77. Find A – B -6 9 -5 A – B = -4 9 -16 5 -8 -4 78. Find 2B – 3A 9 -25 10 2B – 3A = 10 -24 41 -11 24 11 79. Find AB 41 -27 64 AB = 30 -14 23 5 22 -54 80. Find BA 36 11 3 BA = 19 -60 6 -11 -36 -3 81. Find |A| a.
325
c. - 325
b.
375
d. - 375
82. Find |B| a.
27
c. - 72
b.
– 27
d. 72
83. Find AT (or A’) 3 -2 1 AT = 7 6 -8 0 -9 -3 84. Find BT (or B’) 9 2 -4 BT = -2 -3 0 5 7 1
90. What is A ? 6/25 -7/125 A-1 = 1/25 3/125 -2/75 -31/375
21/125 -9/125 -32/375
91. What is the value of: 8
9
0
-2
4
1
-2
3
0
3
2
-4
1
-9
5
3
a.
160
c. 106
b.
– 160
d. – 106
92. What is the value of: -7
0
5
3
10
9
-1
4
6
-3
9
1
4
0
12
3
a.
1374
c. 1734
b.
– 1374
d. – 1734
COMPLEX NUMBER 93. What is the value of i3? a.
i
c. 1
b.
– i
d. – 1
94. What is the value of i12 322 a.
i
c. 1
b.
–i
d. – 1
95. What is the value of i-243 a.
i
c. 1
b.
–i
d. – 1
SITUATION: Given that z1 = 6 – 3i and z2 = 5 + 4i 96. Determine z1 + z2
SITUATION 7: Given the following matrices: 4 0 2 5 7 B = -6 5 A= -1 0 8 1 0 85. Find AB AB = - 15 25 4 0 86. Find BA 8 20 28 BA = -17 -30 -2 2 5 7 SITUATION 8: Given the matrix: 3 7 0 A = -2 6 -9 1 -8 -3 87. What is the minor of A23? 3 1� 3 7� a. � c. � 1 8 7 -8 3 7� -3 1 � b. � d. � 1 -8 7 8
a.
11 + i
c. – 11 + i
b.
11 – i
d. – 11 - i
97. Determine 4z2 - 3z1 a.
25 + 2i
c. 2 + 25i
b.
25 – 2i
d. 2 – 25i
98. Determine z1z2 a.
9 – 42i
c. 42 – 9i
b.
9 + 42i
d. 42 + 9i
99. Determine z1/z2 a. b.
1 41 1 41
(18 + 39i)
c.
(18 - 39i)
d.
1 39 1 39
(18 + 41i) (18 - 41i)
SITUATION: Given that z = 6 – 3i 100. Determine |z| a.
6.780
c. 7.608
b.
6.708
d. 7.806
101. Determine z3 a.
54 + 297i
JOHN REY M. PACTURANAN, CE, MP
c. 297 + 54i
ALGEBRA CE Review May 2021 (EERC) b.
54 – 297i
Page 6 of 6 d. 297 – 54i
102. Determine √z a.
0.595 + 2.521i
b.
0.595 – 2.521i
c.
2.521 + 0.595i
d. 2.521 – 0.595i 103. Determine ln z a.
0.464 – 1.903i
b.
0.464 + 1.903i
c.
1.903 – 0.464i
d.
1.903 + 0.464i
SITUATION 9: Given that z = 5 + 4i 104. Determine |z| a.
6.304
c. 6.403
b.
6.340
d. 6.430
5
105. Determine z a.
-10475 – 2476i
b.
10475 – 2476i
c.
10475 + 2476i
d.
-10475 + 2476i 3
106. Determine �z2 a.
3.105 – 1.499i
b.
-3.105 – 1.499i
c.
-3.105 + 1.499i
d. 3.105 + 1.499i 107. Determine log5z a.
1.154 – 0.419i
b. 1.154 + 0.419i c.
-1.154 – 0.419i
d.
-1.154 + 0.419i
108. Determine ln(-6) a.
1.791 + 3.142i
b.
1.971 – 3.142i
c.
1.791 + 6.232i
d.
1.971 – 6.232i
109. Determine log7(-52) a.
2.031 + 3.142i
b. 2.031 + 1.614i c.
2.031 + 2.231i
d.
2.031 + 2.748i
JOHN REY M. PACTURANAN, CE, MP