How The Gray Tube Works

www.whitedragonpress.com Copyright 2009 – Aaron Murakami – All Rights Reserved

www.whitedragonpress.com Copyright 2009 – Aaron Murakami – All Rights Reserved

www.whitedragonpress.com Copyright 2009 – Aaron Murakami – All Rights Reserved

Video Explanation of How The Gray Tube Works http://www.youtube.com/watch?v=8y0921zaPxQ Discussion Forum http://www.energeticforum.com/renewable-energy/3235-gray-tube-replication.html My explanation appears to be the only thing that is finally consistent with the patents. Theories aside, it doesn't matter if there is electron cascade, RF or anything else. What matters at this point is the mechanics of the step-by-step function of what is happening and I believe I have shown it accurately. Just about everyone, including myself, seems to have believed C1 is discharged into the tube and this causes an outward event that is captured by the grids and that powers the load. This is evidently NOT the case. It is the inverse. John showed electron movement from rods to grids so he knew all along exactly how it worked or what can be taken from his drawings at least that it was C2 that was powering the load. As it was mentioned, the patent does say that but nobody is doing what the patent says. The "choices" that seem to be of debate were primarily with the diode placement. Was Gray wrong and Bedini right? Bedini has it right and I still have reason to believe this. The grids are the standing potential of C2 until LV rod is switched. That standing HV electrostatic potential may or may not be polarizing the ambient air in the tube, special gas, etc... All speculation on gases, vacuum, etc... are evidently not required for the effect although it may be necessary to increase the strength of the effect. None of that is known at this time I don't believe. The Grids are the extension of C2 as an extension to the dipole. The potential is already there and doesn't have to get there. I pointed out in the past but it went unnoticed that even on John's SG's, the positive potential of the battery is ALREADY sitting in the coil. Then when switched on the negative, which it is, it is the negative potential that slams into the coil without resistance...the positive potential doesn't have to encounter resistance entering the coil because it is again, ALREADY sitting there as an extension of the dipole (battery). The Grids are an extension of C2 and the + potential is ALREADY sitting in the inductive load. It doesn't have to move into it and meet resistance. When LV rod is switched on, some serious negative potential (not necessarily electrons at all - anti-photon potential) moves with negative resistance TO the grids, into the load and into the cap. I can see now why at higher voltages and higher speeds that inductive load could get covered with ice. If everyone can see it, the analogy to lightening and how the tube works are not a joke. www.whitedragonpress.com Copyright 2009 – Aaron Murakami – All Rights Reserved

Anyway, C1 gets charged as I show...directly from the power supply, over HV rod directly over gap to the GRIDS, through inductor and to C2...that is exactly how C2 is charged. The C2-cap/Load-inductor, I suppose can be tuned for resonance at whatever frequency the power supply is operating at for maximum efficiency in charging that capacitor. The wire on the Gray motor appears to be pretty large diameter. Then while C2 is charged up -- the commutator or whatever turns on the switch at the LV ROD gives a low potential path to ground for C2 to discharge to. If grids are only covering the HV rod, then C2 can't jump directly to LV rod, it must jump to HV rod first forcing a collision into HV + potential of C1, THEN, it jumps to LV rod back to ground. It is of course very apparent that the power supply + potential is also at the HV rod in addition to whatever charge is in C1...so C2 is colliding with that as well (if and only if the power supply happens to be on a ON cycle at that time). My grids are almost 1 cm from the rods so they obviously need to be closer if C2 is going to be able to discharge during the OFF cycle of the power supply. But if the power supply is operating at 6khz for example, then there will almost be a continuous spark from HV rod to Grids for practical purposes and therefore will act as a conductive pathway for C2 to discharge over towards the Grids. If this is the case, then a wider gap beyond the breakdown gap for C2 can be there. My C2 was discharging as low as about 700 volts over a gap of almost 1 cm from Grids to HV rod and was able to do so only when it met with a HV spark from HV rod to Grid from the power supply. I believe that it makes the most sense to have the grids only over HV rod and not the whole setup for these reasons of forcing the collision with the HV potential of C1. I also think that the spacing between HV rod and Grids should be close enough so that the potential in C2 could discharge when LV Rod is switched on all by itself without having to have the power supply on. With keeping the ROD gap the same, there could be a comparison between C2 discharging by itself with close gap or using HV spark form HV rod and compare coil-popping strength...that is the only sure way to know what is best. The spacing between the HV rod and LV rod should be worked out by having the gap wider and closer and seeing what makes a stronger pop at the coil...that is the only way to know. So, after all, it is about discharging from the Grids (C2) into the tube and not the other way around. PDF of this explanation: How The Gray Tube Works

www.whitedragonpress.com Copyright 2009 – Aaron Murakami – All Rights Reserved