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Production Engineering for All
Analisis Nodal - Introduction to Inflow and Outflow Performance
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NODAL ANALYSIS CONCEPT
Q
Q NODE
INFLOW
Pu
UPSTREAM COMPONENTS
Pn
OUTFLOW
DOWNSTREAM COMPONENTS
Pd
∆Pd
∆Pu ∆P = f (Q)
Pnode = Pu – ∆Pupstream components (1) = f1(Q) Pnode = Pd + ∆Pdownstream components (2) = f2(Q)
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NODE PRESSURE, Pnode
GRAPHICAL SOLUTION OF THE PROBLEM
(2) Outflow from node
NODE PRESSURE
(1) Inflow to node
SYSTEM FLOW CAPACITY FLOW RATE, Q
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EXERCISE # 1 ILUSTRATION OF NODAL ANALYSIS CONCEPT P1= 200 psi
P3= 60 psi ∆P1
Pnode
∆P2
WATER SOURCE 2000 feet, Ø= 3”
1000 feet, Ø=2”
WATER SINK
Calculate: 1) 2)
Actual capacity of the system in BPD. Capacity of the system when the diameter of the 2” pipe is increased to 3”.
Select the node at the point where the pipe diameter is reduced from 3” to 2”. Assume flow rates of 2500, 3000 y 3500, 5000, 5500, 6000 BPD. Use the following equation to calculate the pressure drop in a pipe L Q2 ∆P = 3.8 x 10 - 7 x
; D5
where, ∆P is the pressure drop in psi, L is the pipe length in feet, D is the pipe diameter in inches and Q the flow rate in BPD. Copyright 2007,
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NODE PRESSURE, Pnode
GRAPHICAL SOLUTION OF THE PROBLEM
(2)
2”
Pnode
Outflow performance
(1) Pnode = P1-∆P1 (2) Pnode = P3+∆P2 Inflow (1) performance
Actual system flow capacity
FLOW RATE, Q P1= 200 PSI ∆P1 WATER SOURCE Copyright 2007,
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Pnode
P3= 60 PSI ∆P2 WATER SINK
2000 feet, Ø= 3”
1000 feet, Ø=2”
5
NODE PRESSURE, Pnode
GRAPHICAL SOLUTION OF THE PROBLEM
(2)
2”
Pnode
Outflow performance
(1) Pnode = P1-∆P1 (2) Pnode = P3+∆P2
3” Inflow (1) performance
Actual system flow capacity
FLOW RATE, Q P1= 200 PSI ∆P1 WATER SOURCE Copyright 2007,
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new system flow capacity
Pnode
SOL
P3= 60 PSI ∆P2 WATER SINK
2000 feet, Ø= 3”
1000 feet, Ø=2”
6
Why ‘Nodal’? Pwh
Psep Fluid flows from the reservoir to the stock tank because of the pressure gradients within the system. The total pressure drop from the reservoir to the separator is the sum of the individual pressure drops through four different segments: in the reservoir, across the completion, up the wellbore, and through the flowline. But we do not know the flow rate - that is what we are trying to find. How do we calculate the flow rate, knowing the reservoir and separator pressures? This is the central question of Nodal Analysis. Given the reservoir pressure and the separator pressure, along with the physical properties of each segment, what is the flow rate at which the well will produce?
Reservoir Pwfs Pwf Copyright 2007,
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Pr
• As many ‘nodes’ as you want • The observer can be placed at any node • Normally, the well is observed from bottom hole, Pwf
7
Pressure Losses in Well System ∆P4 = (Pwh - Psep)
Gas
Pwh
Psep
Sales line
Liquid
Stock tank
∆P3 = Pwf - Pwh
Pwf
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∆P1 = Pr - Pwfs
= Loss in reservoir
∆P2 = Pwfs - Pwf
= Loss across completion
∆P3 = Pwf - Pwh
= Loss in tubing
∆P4 = Pwh - Psep
= Loss in flowline
∆PT = Pr - Psep
= Total pressure loss
Pwfs
∆P1 = (Pr - Pwfs) ∆P2 = (Pwfs - Pwf)
Pr
Pe
Adapted from Mach et al, SPE 8025, 1979.
8
Nodal Analysis How do we determine the right flow rate? We know the separator pressure and the average reservoir pressure. We start in the reservoir at the average reservoir pressure, Pr, and assume a flow rate. This lets us calculate the pressure just beyond the completion, Pwfs. We can then calculate the pressure drop across the completion, and the bottomhole pressure Pwf. This pressure is valid only for the assumed flow rate. Or, we may start at the separator at Psep, and calculate the pressure drop in the flowline to find the wellhead pressure, Pwh. Then we can calculate the bottomhole pressure Pwf. Again, this pressure is valid only for the assumed flow rate. The two calculated bottomhole pressures will probably not be the same. If not, then the assumed rate is wrong. “Nodal” analysis refers to the fact that we have to choose a point or “node” in the system at which we evaluate the pressure - in this case, the bottom of the wellbore. This point is referred to as the solution point or solution node. Copyright 2007, , All rights reserved
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Well Outflow Performance
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RESERVOIR INFLOW PERFORMANCE Psep Pwf
∆P flowline
GAS
Pwh
Flowline
OIL +WATER
Q
Separator
Tubing
∆Pres = f(Q)
∆Ptubing
Reservoir
INFLOW Pwf
Pr, IPR, K
NODE, All(Pwf) rights reserved
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∆Pres
Q
11
Types of Outflow Systems
Single / multiple
selective / non-selective
flowing / lifted – gas-lifted – pumped • • • • •
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beam pump ESP PCP Jet Pump Hydraulic Pump
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WELLBORE FLOW PERFORMANCE (OUTFLOW) Psep Pwf
∆P flowline
GAS
Pwh
Flowline
OIL +WATER
Q
Separator
Tubing
∆Ptbg = f(Q)
∆Ptubing
Reservoir
OUTFLOW Pwf
Pr, IPR, K
NODE, All(Pwf) rights reserved
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∆Pres
Q
13
SINGLE PHASE FLOW BASIC CONCEPTS FLUID VELOCITY Is the flow rate (q) divided by the pipe cross sectional area (A) through which the fluid flows at the pressure and temperature conditions of the pipe element
q
A
v P,T
v=q/A Copyright 2007,
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FUNDAMENTALS OF FLUID FLOW IN PIPES
FLOW GEOMETRY
Z δP/δZ
θ
GENERAL ENERGY EQUATION ∆P (
)T=( ∆L
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∆P
∆P ) acceleration + (
∆L
∆P ) elevation + (
∆L
) friction ∆L
15
FUNDAMENTALS OF FLUID FLOW IN PIPES
∆P ( ∆L
ρ )elevation =
∆P ( ∆L
ρ v )friction = f
∆P ( ∆L
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144
2
2gd
ρ ∆( v 2) )acc =
2g ∆L
16
FRICTION LOSSES CALCULATION (single phase flow) ∆P ( ∆L
ρv2 )f = f
2gd
where f, is the friction factor which is a function of the pipe roughness (ε) and theReynolds Number (NRe), which is calculated fromthe following equation:
dvρ
NRe =
µ µ is the viscosity in lbm/ft-sec 1cps= 0.00067197 lbm/ft-sec
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Friction Factor Calculation (single phase flow)
Depends on the flow regime: 64 For laminar flow
NRe < 2000
For turbulent flow NRe > 2000.
f= NRe ε √1/ f = - 2 log (
2.51 +
3.71d
) NRe√ f
The latest equation requires a trial and error process to calculate f An intial value to start the iterative process can be obtained from the following equation: f = 0.0056 + 0.5 NRe - 0.32
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Moody Diagram for Friction Factor Calculation
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EXERCISE 10 SINGLE PHASE FLOW
Calculate the friction pressure drop in a section of horizontal pipeline of 3000 ft length and 3.937 inches internal diameter, where 5000 STB/D of 0.9 sp. gr. oil with a viscosity of 5 cps oil are flowing. The absolute pipe wall roughness is 0.006 ft.
q
v
A
1cps= 0.00067197 lbm/ft-sec 1 Bbl=5,615 Ft3 1 day=86400 sec
v=q/A dvρ NRe =
µ
∆P
f
from Moody
( ∆L
ρv2 )f = f
2gd
ε/D sol Copyright 2007,
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Oil Reservoir Phase Envelop Single Phase Region (Liquid)
Pres
% Liquid
C
e
Psep
50 25 20 15 10 5 0
Gas
Temperature Copyright 2007,
Lin e
as h P
Re
on i g
Po int
o w T
Pb
De w
Pressure
ine L int o P e l bb u B 100 75
Single Phase Region (Gas)
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21
MULTIPHASE FLOW PRESSURE GRADIENT EQUATION FOR TWO-PHASE FLOW:
∆P (
∆P )T=(
∆L
) acceleration + ( ∆L
∆P ( ∆L
)elevation =
∆P ( ∆L
)friction = f
∆P ( ∆L
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∆P
)acc =
∆P ) elevation + (
∆L
) friction ∆L
ρm 144 ρm v m 2 2gd ρm ∆( vm 2) 2g ∆L
22
GRAVITY TERM
∆P ( ∆L
)elevation =
ρm 144
Correcting weight of fluid Dominant term Single phase simple Multiphase complex
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FRICTION TERM
∆P ( ∆L
)friction = f
ρm v m 2 2gd
Increases with rate Proportional to velocity Proportional to relative roughness Laminar vs turbulent flow Effect of viscosity Effect of mixture density Sensitive to gas volumes
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ACCELERATION TERM
∆P ( ∆L
)acc =
ρm ∆( vm 2) 2g ∆L
Expansion of fluid as pressure decreases Smallest term Often ignored Need to account in high rate
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BASIC CONCEPTS Mixture Velocity, V (Two-phase flow) L
qg
v
qL
A
Pipe element with liquid and gas travelling at the same velocity, V
v = (qL+qg) / A
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No-Slip Liquid Holdup (Input Liquid Content), λ
Ag
qg
L
v
qL
Ap
P,T
AL RATIO OF THE VOLUME OF LIQUID IN A PIPE ELEMENT THAT WOULD EXIST IF THE GAS AND THE LIQUID TRAVELED AT THE SAME VELOCITY (NO SLIPPAGE) DIVIDED BY THE VOLUME OF THE PIPE ELEMENT.
λ = AL /AP = qL / (qL + qg)
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No-Slip Liquid Holdup (Input Liquid Content), λ
Ag
qg
L
v
qL
Ap
P,T
AL
RATIO OF THE VOLUME OF LIQUID IN A PIPE ELEMENT THAT WOULD EXIST IF THE GAS AND THE LIQUID TRAVELED AT THE SAME VELOCITY (NO SLIPPAGE) DIVIDED BY THE VOLUME OF THE PIPE ELEMENT.
λ = AL /AP = qL / (qL + qg) However, the gas velocity is higher than the liquid velocity and as a consequence the volume of liquid in the pipe element increases. This phenomenon is known as “slippage between phases” , and the volumen fraction occuppied by the liquid in the pipe element under this conditions is known as“Hold-Up Factor” (HL), and is dependent on flow pattern, gas and liquid properties, pipe diameter and pipe inclination. Copyright 2007,
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Superficial Gas Velocity, VSG
Ag
qg
L
v
qL
Ap
AL Pipe element with liquid and gas travelling at the same velocity, V
vSG = qg / Ap Is the velocity that the gas phase would exhibit if it flowed through the total cross sectional area of the pipe alone.
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Superficial Liquid Velocity, VSL
Ag
qg
L
v
qL
Ap
AL Pipe element with liquid and gas travelling at the same velocity, V
vSL = qL / Ap Is the velocity that the liquid phase would exhibit if it flowed through the total cross sectional area of the pipe alone.
Vm= Vsl + Vsg Copyright 2007,
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Vertical Flow Parameters Temperature
Pressure
chum flow bubble flow
Depth
slug flow
Approximate linear temperature profile
Singlephase oil p > pBP oil Copyright 2007,
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Two-Phase Vertical Flow Analysis and Calculations are Complex 1 Flow regime (gas distribution) Mist Flow Decreasing Pressure
Annular Flow Churn Flow Plug OR Slug Flow Bubble Flow Single Phase Liquid Flow
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2 Proportion gas vs liquid changes 3 Gas tends to rise faster than liquid (slippage) Factors affecting ∆Pvert. 1 Mass flow rate: Oil Rate Gas Rate (GLR) Water Rate (CUT)
2 Physical properties PVT Viscosity Surface tension
3
Conduit Configuration Size Roughness Concentric?
4 Pressure 5 Temperature
32
Vertical Flow Paterns
BUBBLY Copyright 2007,FLOW , All rights reserved
SLUG FLOW
CHURN FLOW
ANNULAR FLOW
33
Horizontal Flow Paterns Annular Dispersed
Stratified Wavy
Slug (Intermitent)
Dispersed Bubble Copyright 2007,
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2-Phase –Gas-Liq) Flow Regimes
Flow regime or Flow Pattern : is a qualitative description of the phase distribution in a pipe.
4 regimes are generally agreed upon: 1. BUBBLE FLOW: dispersed bubbles of gas in a continuous liquid phase 2. SLUG FLOW: at higher rates, the bubbles coalesce into larger bubbles, which eventually fill up the entire pipe section. Between the large gas bubbles are slugs of liquid that contain smaller bubbles of gas entrained in the liquid.
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2-Phase –Gas-Liq) Flow Regimes 3. CHURN FLOW: with further increase in gas rate, the larger gas bubbles become unstable and collapse, resulting in a highly turbulent pattern. Both phases are dispersed. Churn flow is characterized by oscillatory up-and-down motions of liquid. 4. ANNULAR FLOW: at higher rates, gas becomes the continuous phase, with liquid flowing in an annulus coating the surface of the pipe and with liquid droplets entrained in the gas phase.
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Flow Regime (Ros)
TR B AN U S B SL BL ITIO U E N G /
1 0.5 0.2 0.1
SLUG FLOW PLUG FLOW
TRA SLU NSITI O G/ MIS N T
SL UG
*
FROTH FLOW RN
BUBBLE FLOW
RN
R
10
R MI N ST
RN TR AN
N
B
SL UG
*
U
B
FN
100
As µ, Increases, heading regime may range up to
HEADING
MIST FLOW
0.05 0.02 0.01 0.1
0.2 0.3
0.5 0.7 1
2
3
5
7 10
RN RN = Dimensionless Gas Velocity Number Copyright 2007, All rights reserved FN = , Dimensionless Liquid Velocity Number
100
1000 37
CORRELATIONS Babson (1934) Gilbert (1939 / 1952) Poettmann & Carpenter (1952) Duns & Ros Hagedorn & Brown Orkiszewski Aziz, Govier and Fogarasi Chierici et al Fancher & Brown Beggs &Brill Duckler Flannigan Gray H.MONA, Asheim Hasan and Kabir Copyright 2007,
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PROCEDURE FOR PRESSURE TRAVERSE CALCULATION (incrementing pressure drop)
1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16.
Starting with the known pressure value, P1, at location L1, select a length increment ∆L. Estimate a pressure drop, ∆P, corresponding to the length increment, ∆L. Calculate the average pressure and temperature in the selected pipe element. Calculate the the fluids PVT properties at the average conditions of P and T. Calculate fluids densities and flow rates at the average conditions. Calculate the input liquid content, λ and the superficial velocities vsl and vsg. Determine the flow regime pattern. Calculate the hold-up factor, HL, corresponding to the stablished flow regime pattern. Calculate the mixture properties for the calculated hold-up factor. Calculate the two-phase friction factor. Calculate the total pressure gradient in the increment of pipe at the average conditions of P and T. Calculate the pressure drop corresponding to the selected length increment. Compare the estimated and calculated pressure drop. If they are not sufficiently close, estimate a new pressure drop an repeat the procedure from steps 3 through 13. Repeat steps 3 through 13 until the estimated and calculated values are sufficiently close. Calculate a new position L2 = L1 + ∆L and the corresponding pressure P2 = P1 + ∆P. Repeat steps 1 through 15 until the total pipe length is completely covered.
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L2
P2
∆L ∆P
L1
P1 39
Outflow Calculation (node at the bottomhole) Pressure
Pwf1
Depth Equv. . To Pwh
Pwh
Pwf2
Q
Q1
Q2
Pwf
Pwf1
Pwf2
Q3 Pwf3
Tubing Depth
Pwf3
Q1
Q2 Outflow Pwf
Q3 Pwf1 Pwf3 Pwf2
q1 Copyright 2007,
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q2
q3
Q 40
Well Performance Software The most noteworthy well performance programs on the market today are:
Prosper
(Petroleum Experts)
WellFlo
(Edinburgh Petroleum Services)
Perform
(Dwight’s / IHS Energy Services)
PipeSim
(Schlumberger)
WEM
(P.E. Mosely & Associates)
In addition to these programs, numerous other well performance programs have been developed for commercial or private use. Copyright 2007,
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BOTTOMHOLE FLOWING PRESSURE, Pwf
EFFECT OF THE TUBING SIZE (NODE SELECTED AT THE BOTTOMHOLE)
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d1
Pr
d2>d1
INFLOW IPR
OUTFLOW
0
0
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FLOWRATE, Q
42
FLOW RATE, Q
FINDING OPTIMUM TUBING SIZE
UNSTABLE REGION DIAMETER FOR MAXIMUM FLOW RATE
TUBING DIAMETER, d Copyright 2007,
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Tubing Size in Depleting Reservoir 1“ Pinitial Tubing Intake Pressure
2 3/8 “ 3 1/2 “
P5 4 1/2 “
Pwf
5“
P10
Q Copyright 2007,
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Effect of Gas Injection Rate 0 400
50
300 100 150
P 200
IPR 250
Qmax Copyright 2007,
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Gas Lift Performance Curve Technical Optimum
SLOPE = 1.0 Economic Limit 4 ∆x Kick-Off Lift-Gas Requirement
2 Initial Oil Rate at Kick-off 3 Technical cut-off limit 4 Max. Oil Rate
∆x
Incremental Lift-Gas Volume
∆x ∆x
NET OIL PRODUCTION OR REVENUE
1
∆x
∆x
∆x ∆x ∆x ∆x
2 ∆x
3 1 Copyright 2007,
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LIFT-GAS INJECTION RATE OR PRODUCTION COSTS
46
Inflow Performance Curve 3500
Flowing bottomhole pressure, psi
Inflow (Reservoir) Curve
Pr
3000
Performance of an ideal OH well, no damage, no completion, no friction losses from reservoir to wellhead
2500
2000
1500
1000
AOFP
500
0 0
500
1000
1500
2000
2500
3000
3500
4000
4500
Production rate, STB/D Copyright 2007,
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Outflow Performance Curve
Flowing bottomhole pressure, psi
3500
Outflow (Tubing) Curve
3000
2500
2000
Tubing Performance Curve
1500
1000
500
0 0
500
1000
1500
2000
2500
3000
3500
4000
4500
Production rate, STB/D Copyright 2007,
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System Graph
Flowing bottomhole pressure, psi
3500
Inflow (Reservoir) Curve Outflow (Tubing) Curve
3000
2500
1957.1 psi 2000
1500
1000
500
2111 STB/D
0 0 Copyright 2007,
500
, All rights reserved
1000
1500
2000
2500
3000
Production rate, STB/D
3500
4000
4500 49
System Graph – Wellhead Node 1600
Inflow Curve Outflow Curve
Flowing wellhead pressure, psi
1400 1200 1000 800
500 psi 600 400 200
2050 STB/D
0 0 Copyright 2007,
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500
1000
1500
2000
Production rate, STB/D
2500
3000 50
Nodal Analysis: Uses
Estimation of Reservoir Parameters – – – –
Skin Permeability Reservoir Pressure Note : Non unique solutions unless only one unknown
Evaluation of Potential Stimulation Treatments – Primarily through reduction in skin – Parameter sensitivity studies are important
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Nodal Analysis Two Main Components Inflow Performance Curve/Relationship (IPR)
– Oil or Gas Flowrate vs Bottomhole Flowing Pressure – Ordinate Origin = Reservoir Pressure (∆P = 0 q = 0) – Abscissa Intercept = Absolute Open Flow Potential (∆P = Pr
q = Max)
Outflow Curve (Tubing Intake)
– Function of Hydrostatic, Friction & Acceleration Components – Curves Shifted by Wellhead Pressure & Artificial Lift
Intercept of Curves Gives FBHP (psi) & Flowrate
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Nodal Analysis Reservoir Pressure
Pressure at Node
Inflow
Operating Point
Pressure PWF
Outflow
Operating Flowrate
Flowrate (stb/d)
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The Inflow Performance Relationship Dependent On:
Fluid Properties – Oil • •
Viscosity, Gas oil Ratio, Bubble Point Formation Volume Factor, Density
– Gas • •
Viscosity, Z Factor, Compressibility Density
Inflow Correlation Used e.g. Oil - Darcy, Vogel, Gas - Jones, Darcy Well Geometry i.e. Vertical or Horizontal Formation Properties – – – –
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Reservoir Pressure Permeability Skin (Includes deviation, perforation, damage etc) Net Pay Height
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Effect of Skin in IPR
Pressure at Node
qO α
Inflow (IPR)
Outflow
5
0
Flowrate , All rights reserved
⎛r ⎞ ln⎜⎜ e + s ⎟⎟ ⎝ rw ⎠
SKIN 10
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1
-1
-3
Note : Log effect 55
Effect of Pressure Depletion in IPR
Pressure at Node
Reservoir with no pressure support
Inflow
Outflow
Oil Recovery (% STOIIP) 12
8
4
0
Flowrate Copyright 2007,
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The Outflow Performance Relationship Dependent On: Fluid Properties – Oil • •
Viscosity, Gas oil Ratio, Bubble Point Formation Volume Factor, Density
– Gas • •
Viscosity, Z Factor, Compressibility Density
Outflow Correlation Used e.g. Oil - Duns & Ross, Gas - Gray Friction Completion Properties • • •
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Tubing Size Tubing Restrictions Tubing Roughness
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Effect of Tubing Size in Outflow For a Tubing Restricted Well
Pressure at Node
Inflow (IPR) Outflow 2 3/8” 2 7/8”
3 1/2”
4 1/2”
Flowrate (stb/d) Copyright 2007,
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