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CASE: JCG Global Air Services Quantitative Techniques- II Assignment: - 04 Section: - F Group number: 7

Submitted To: Prof. Bhuvanesh Pareek Submitted By: Akhilesh Kumar Singh Gaurav Panda Indroneel Das Mugdha Kabra Nikhil Murthy Swetapadma Mahapatra Shibani Shankar Ray

Given Information:

Fuel Costs per gallons: Airport KMLI KBOS KTEB KDAL

Price ($ per Gallons) 3.97 8.35 7.47 6.01

Ramp fee Waivers on purchase of fuel Airport

Ramp Fee

Min Gallons for fee Waiver

KMLI KBOS KTEB KDAL

800 450 400

500 300 350

Assumptions: Let the amount of fuel purchased at each airport be as follows: X1: Fuel gallons at airport KMLI before journey X2: Fuel gallons at airport KBOS X3: Fuel gallons at airport KTEB X4: Fuel gallons at airport KDAL X5: Fuel gallons at airport KMLI after Journey Before are the binary variables that identify the use of ramp fee waivers: Y1: Waiver at KBOS Y2: Waiver at KTEB Y3: Waiver at KDAL Y1, Y2 and Y3 are binary variables with values only 0 and 1. X1, X2, X3, X4 and X5 are integer Variables Objective Function: Objective is to minimize the costs incurred in the flight for the planned travel Minimize 3.97*X1 + 8.35*X2 + 7.47*X3 + 6.01*X4 + 3.97*X5 + Y1*800 + Y2*450 + Y3*400 Subject to Constraints:

Fuel tank Constraints X1 + 7000 <= 13000 7000 + X1 – 4800 + X2 <= 13000 7000 + X1 – 4800 + X2 – 2000 + X3 <= 13000 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 + X4 <= 13000 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 + X4 – 3100 + X5 <= 13000 Minimum Fuel Constraints 7000 + X1 – 4800 >= 2400 7000 + X1 – 4800 + X2 – 2000 >= 2400 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 >= 2400 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 + X4 – 3100 >= 2400 Maximum Ramp Weight Constraints 22200 + 7000 + X1 + 2*200 <= 36400 22200 + 7000 + X1 – 4800 + X2 + 4*200 <= 36400 22200 + 7000 + X1 – 4800 + X2 – 2000 + X3 + 8*200 <=36400 22200 + 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 + X4 + 8*200 <= 36400 Maximum Landing Weight Constraints 22200 + 7000 + X1 – 4800 + 2*200 <= 31800 22200 + 7000 + X1 – 4800 + X2 – 2000 + 4*200 <= 31800 22200 + 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 + 8*200 <= 31800 22200 + 7000 + X1 – 4800 + X2 – 2000 + X3 – 5300 + X4 -3100 + 8*200 <= 31800 Relation between X and Y 500 * 6.7 * (1- Y1) <= X2 300 * 6.7 * (1-Y2) <= X3 350 * 6.7 * (1-Y3) <= X4

Solving The LP using simplex we get

Microsoft Excel 15.0 Answer Report Worksheet: [288508646-Sectiond-Group14-Jcg-Global-Airservice.xlsx]CE 750 Formulation Report Created: 12/7/2015 2:32:08 AM Result: Solver found a solution. All Constraints and optimality conditions are satisfied. Solver Engine Engine: Simplex LP Solution Time: 0 Seconds. Iterations: 20 Subproblems: 0 Solver Options Max Time Unlimited, Iterations Unlimited, Precision 0.000001 Max Subproblems Unlimited, Max Integer Sols Unlimited, Integer Tolerance 1%, Assume NonNegative

Objective Cell (Min) Cell $B$14

Variable Cells Cell $B$5 $C$5 $D$5 $E$5 $F$5 $B$9 $B$10 $B$11

Constraints

Name Minimize KMLI

Name Fuel to be bought Fuel to be bought Fuel to be bought Fuel to be bought Fuel to be bought KBOS KMLI KTEB KMLI KDAL KMLI

KMLI KBOS KTEB KDAL KMLI

Original Value 11645.16 418

Final Value 11645.164 18

Original Value 6000 0 2010 2590 4600 1 0 0

Final Value 6000 0 2010 2590 4600 1 0 0

Integer Integer Integer Integer Integer Integer Binary Binary Binary

Cell

Name

$A$18

Relation between X and Y –

$A$19

Relation between X and Y –

$A$20

Relation between X and Y –

$A$22

Fuel Tank constraints –

$A$23

Fuel Tank constraints –

$A$24

Fuel Tank constraints –

$A$25

Fuel Tank constraints –

$A$26

Fuel Tank constraints –

$A$28

$A$35

Minimum Fuel Constraints – Minimum Fuel Constraints – Minimum Fuel Constraints – Minimum Fuel Constraints – Minimum Fuel on arrival at KMLI Maximum Ramp Weight -

$A$36

Maximum Ramp Weight -

$A$37

Maximum Ramp Weight -

$A$38

Maximum Ramp Weight -

$A$40

Maximum Landing weight -

$A$41

Maximum Landing weight -

$A$42

Maximum Landing weight -

$A$43

Maximum Landing weight -

$A$29 $A$30 $A$31 $A$33

$B$5:$F$5=Int eger $B$9:$B$11= Binary

Cell Value

Formula

0 $A$18<=$ B$18 2010 $A$19<=$ B$19 2345 $A$20<=$ B$20 13000 $A$22<=$ B$22 8200 $A$23<=$ B$23 8210 $A$24<=$ B$24 5500 $A$25<=$ B$25 7000 $A$26<=$ B$26 8200 $A$28>=$ B$28 6200 $A$29>=$ B$29 2910 $A$30>=$ B$30 2400 $A$31>=$ B$31 7000 $A$33>=$ B$33 35600 $A$35<=$ B$35 31200 $A$36<=$ B$36 32010 $A$37<=$ B$37 29300 $A$38<=$ B$38 30800 $A$40<=$ B$40 29200 $A$41<=$ B$41 26710 $A$42<=$ B$42 26200 $A$43<=$ B$43

Status Binding

Sla ck 0

Binding

0

Not Binding Binding

245

Not Binding Not Binding Not Binding Not Binding Not Binding Not Binding Not Binding Binding

480 0 479 0 750 0 600 0 580 0 380 0 510

Binding

0

Not Binding Not Binding Not Binding Not Binding Not Binding Not Binding Not Binding Not Binding

800

0

0

520 0 439 0 710 0 100 0 260 0 509 0 560 0

Sensitivity Analysis: Variable Cells

Cell $B$ 5 $C$ 5 $D$ 5 $E$ 5 $F$ 5 $B$ 9 $B$ 10 $B$ 11

Name Fuel to be bought KMLI Fuel to be bought KBOS Fuel to be bought KTEB

Fin al Val ue 600 0 0

Reduce d Cost

Allowab le Increase

0

Objectiv e Coeffici ent 0.592537 313 1.246268 657 1.114925 373 0.897014 925 0.592537 313 800

0.005970 149 0.110447 761 0.304477 612 370

0.110447 761 0.217910 448 0.005970 149 0.592537 313 800

0 0.110447 761 0

0.304477 612 1E+30

Allowabl e Decreas e 1E+30

KBOS KMLI

201 0 259 0 460 0 1

KTEB KMLI

0

12

450

1E+30

12

KDAL KMLI

0

400

400

1E+30

400

Fin al Val ue 0

Shadow

Constrai nt R.H. Side 0

Allowab le Increase 3350

Allowabl e Decreas e 1E+30

0

510

245

0

1E+30

245

0.304477 612 0

13000

245

510

13000

1E+30

4800

0

13000

1E+30

4790

0

13000

1E+30

7500

Fuel to be bought KDAL Fuel to be bought KMLI

0 0

Constraints

Cell

Name

$A$ 18

Relation between X and Y –

$A$ 19

Relation between X and Y –

201 0

$A$ 20 $A$ 22

Relation between X and Y – Fuel Tank constraints –

234 5 130 00

$A$ 23 $A$ 24 $A$ 25

Fuel Tank constraints –

820 0 821 0 550 0

Fuel Tank constraints – Fuel Tank constraints –

Price 0.238805 97 0.217910 448 0

$A$ 26 $A$ 28 $A$ 29 $A$ 30 $A$ 31 $A$ 33 $A$ 35 $A$ 36 $A$ 37 $A$ 38 $A$ 40 $A$ 41 $A$ 42 $A$ 43

Fuel Tank constraints – Minimum Fuel Constraints – Minimum Fuel Constraints – Minimum Fuel Constraints – Minimum Fuel Constraints – Minimum Fuel on arrival at KMLI Maximum Ramp Weight Maximum Ramp Weight Maximum Ramp Weight Maximum Ramp Weight Maximum Maximum Maximum Maximum -

Landing weight Landing weight Landing weight Landing weight

700 0 820 0 620 0 291 0 240 0 700 0 356 00 312 00 320 10 293 00 308 00 292 00 267 10 262 00

0

13000

1E+30

6000

0

2400

5800

1E+30

0

2400

3800

1E+30

0

2400

510

1E+30

0.304477 612 0.592537 313 0

2400

4600

245

7000

6000

4600

36400

1E+30

800

0

36400

1E+30

5200

0

36400

1E+30

4390

0

36400

1E+30

7100

0

31800

1E+30

1000

0

31800

1E+30

2600

0

31800

1E+30

5090

0

31800

1E+30

5600

Limits Report:

Cell $B$ 14

Objective Name Minimize KMLI

Value 11645.16 418

Variable Cell $B$ 5 $C$ 5

Name Fuel to be bought KMLI Fuel to be bought KBOS

Value 6000 0

Low er Lim it 600 0 0

Objectiv e Result 11645.16 418 11645.16 418

Upp er Lim it 600 0 260 0

Objectiv e Result 11645.16 418 14885.46 269

$D$ 5 $E$ 5 $F$ 5 $B$ 9 $B$ 10 $B$ 11

Fuel to be bought KTEB Fuel to be bought KDAL Fuel to be bought KMLI KBOS KMLI

2010

1

201 0 259 0 460 0 1

KTEB KMLI

0

0

KDAL KMLI

0

0

2590 4600

11645.16 418 11645.16 418 11645.16 418 11645.16 418 11645.16 418 11645.16 418

Hence Optimal Fuel to be bought are: Airport KMLI KBOS KTEB KDAL KMLI

Fuel ( in Gallons) 6000 0 2010 2590 4600

The Ramp fee waiver is used at Airport KBOS.

640 0 819 0 106 00 #N/ A #N/ A #N/ A

16539.68 657 16668.44 776 15200.38 806 #N/A #N/A #N/A

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